Math, asked by mahashiv616, 2 months ago

If NaOH used for preparation of 1 N solution is
90% pure; then how much absolute error occur
ml) when titrated adainst 10ml 1N HCl solution
marks
Ans.
10ml
10.1 ml
11ml
11.1 ml​

Answers

Answered by gavrav424242
1

Answer:

10ml is the right ans.

I hope it helps you

Answered by anvitanvar032
0

Answer:

The correct answer to this question is 10ml titrated adainst 10ml 1N HCl solution.

Step-by-step explanation:

Given - NaOH used for preparation of 1 N solution is 90% pure.

To Find - how much absolute error occur  when titrated adainst 10ml 1N HCl solution.

NaOH used for preparation of 1 N solution is 90% pure and 10ml titrated adainst 10ml 1N HCl solution.

Sodium chloride is typically electrolyzed in a Castner-Kellner cell to prepare it. Using a carbon anode and a mercury cathode, a brine solution is electrolyzed. Sodium amalgam is created when mercury and sodium metal from the cathode mix. The cathode is where Cl gas is evolved. Producing soap, rayon, paper, explosives, dyestuffs, and petroleum products all require sodium hydroxide. The processing of cotton fabrics, metal cleaning and processing, oxide coating, electroplating, and electrolytic extraction are further uses for it.

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