Question

If NaOH used for preparation of 1 N solution is
only 90% pure; then how much absolute error
occurs (in ml) when titrated adainst 10ml 1N
HCl solution? (1 marks)​

Answer 1

Explanation:

Making 1 N solution of NaOH

To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume 1 liter. For a 0.1 N solution (used for wine analysis) 4.00 g of NaOH per liter is needed.

Answer 2

To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume 1 liter. For a 0.1 N solution (used for wine analysis) 4.00 g of NaOH per liter is needed.

If NaOH used for preparation of 1 N solution isonly 90% pure; then how much absolute error occurs (in ml) when titrated adainst 10ml 1N.

to make 90% pure for preparation of 1N solution, absolute error made against 10mL 1N HCL Solution is

$0.09*40=36g$

36 g of NaoH is required,

so absolute error occurs is equal to

$40-36/40\\=4/40\\=0.1$

So, Absolute error is 10%