Question

If nc1 nc2 and nc3 are in AP then find nc1 + nc2 +nc3.


Answer is 63

Answer 1

The value of nc1 = 16 , nc2 = 21 and nc3 = 26

Given:

nc1 + nc2 + nc3 = 63

To find:

The value of nc1 , nc2 and nc3

Solution:

nc1, nc2, and nc3 are in arithmetic progression (AP), that means that they are a sequence of numbers such that the difference between any two consecutive terms is constant. This constant is known as the common difference.

In general, the sum of an arithmetic series is given by:

Sum = (number of terms) * (average of first and last term)

In this case, the sum of nc1, nc2, and nc3 is given by:

Sum = 3 * (nc1 + nc3) / 2

Since the sum is 63, we can set up the equation:

63 = 3 * (nc1 + nc3) / 2

Solving this equation gives:

nc1 + nc3 = 42

Since nc1, nc2, and nc3 are in AP, we know that the difference between any two consecutive terms is constant. Let's call this constant "d".

That means that nc1 = nc2 - d and nc3 = nc2 + d.

Substituting these equations into the equation nc1 + nc3 = 42 gives:

nc2 - d + nc2 + d = 42

Solving this equation gives:

nc2 = 21

Therefore, the value of nc1 = 16 , nc2 = 21 and nc3 =

26

SPJ1