if nc10=nc6 find 11c11. please answer me fast!!!
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Answered by
0
Answer:
nCr= n!/r!×(n-r)!
11c11=11!/11!×(11-11)!
=1/0!
=1. (0! =1
Answered by
0
We will get answer as 1.
Step-by-step explanation:
In permutation and combination we have formula for combinations as
⇒C(n,r)= n!/r!(n-r)!
⇒P(n,r)=n!/(n-r)!
⇒Here ,in the question we are given ,to find the value of C(11,11)
So, putting the values in the equation
⇒C(11,11)=11!/11!(11-11)!
⇒We will get 11!/11!×0!
⇒which is equal to 1.
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