If near point of a person is 75 cm from eye what is power of lens required to correct his sight
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u = - infinity
v = -75 cm
1 /-(-d) - 1/ u = 1 /f
1 /75 - 1/ infinity = 1 /f
1 /f = 1 /75
f = 75 cm
Power(P) = 1 /f in meters
P = 100 /75
P = +1.34 D
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