Question

If near point of eye is x metres for a defective eye and the far point is y metres for the same eye. Find the power of lens required.

CLASS 10 -HUMAN EYE

NO SPAMMING​

Answer 1

Step-by-step explanation:

Near point - 25cm

Far point - infinity

In cas of a Myopic eye,

U(object distance) = infinity

V(image distance) = 25cm

So,

1/v - 1/u = 1/f

1/(-25)= 1/f

f= (-25)cm

P= 1/f -> 1/(-25)= (-0.4)cm= -4m....

Similarly, for hypermetropic eye.....

Take U= (-25)cm and V = dis. of the image....