If new velocity of body is twice of previous velocity then kinetic energy will be
A 2times B 0.5 times
C 4 times. D. 6 times
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Answered by
3
your answer Is c 4 times
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Answered by
9
since
kinetic energy (kE)=mv^2/2
we see that mass is constant and 1/2 is also
so
kE= v^2
initial kE/finakKE=v^2/4v^2
4initial kE=final kinetic energy
so ratio is 1:4
so 4 times
option c
kinetic energy (kE)=mv^2/2
we see that mass is constant and 1/2 is also
so
kE= v^2
initial kE/finakKE=v^2/4v^2
4initial kE=final kinetic energy
so ratio is 1:4
so 4 times
option c
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