If nineth term of an A.P. is zero then show that 29th term is double the 19th term
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Answered by
2
Answer:
The 29th term of the AP is twice the 19th term
Step-by-step explanation:
= Let a and d respectively be the first term and common difference of the AP
Given a9 = 0
so, a+(n-1)d =0
a+(9-1)d=0
Now, 29th term = a+28d
= -8d + 28d
20d = 2× 10d
= 2(-8d+18d)
= 2(a+18d)
= 2×19th term
Thus, the 29th term of the AP is twice the 19th term.
Answered by
1
Answer:
Step-by-step explanation:
Let a and d are first term and cd
T9=a+8d=0
Then 29th term
T29=a+28d
=2a+36d-a-8d
=2(a+18d) -(a+8d)
=2T19-0
T29=2T19
proved
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