if niti drives her car at to km/hr from her home,she reaches the office late by 10min.however if she drives at 60km/hr,she reaches the office 5 minutes early .find the distance of the office from her home.
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Hi,
Let d be the distance
let t be the time taken (without being early or late)
the hint here is that the distance remains same in both cases
so the distances in given two cases can be equated to each other
speed = distance / time
distance = speed * time
50*(t+10/60) = 60*(t-5/60)
=> 50t + 500/60 = 60t - 5
=> 10t = 500/60 + 5
=> 10t = 800/60
=> t = 80/60 = 4/3 hrs
note: 10 minutes = 10/60 hrs & similarly 5 minutes = 5/60 hrs
so distance
= 60*(t-5/60)
= 60t - 5
= 60*(4/3) - 5
= 240/3 - 5
= 80 - 5
= 75 km
So the distance of the office from home is 75 km
Hope it helped.
Let me know if any doubts.
Cheers !!!
Let d be the distance
let t be the time taken (without being early or late)
the hint here is that the distance remains same in both cases
so the distances in given two cases can be equated to each other
speed = distance / time
distance = speed * time
50*(t+10/60) = 60*(t-5/60)
=> 50t + 500/60 = 60t - 5
=> 10t = 500/60 + 5
=> 10t = 800/60
=> t = 80/60 = 4/3 hrs
note: 10 minutes = 10/60 hrs & similarly 5 minutes = 5/60 hrs
so distance
= 60*(t-5/60)
= 60t - 5
= 60*(4/3) - 5
= 240/3 - 5
= 80 - 5
= 75 km
So the distance of the office from home is 75 km
Hope it helped.
Let me know if any doubts.
Cheers !!!
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