Question

if no of digit in X^100 is 31.then find the number of digit in
X^1000.

Answer 1

Answer:

If x100 is 31 digit number Then x1000 contains how many digits.

Our Approach:

101 has 2 digits = 10

102 has 3 digits = 100

103 has 4 digits = 1000

1030 has 31 digits

therefore, 1030=x100

30=100logx

multiplying both sides by 10

30⋅10=10⋅100logx

300=1000logx=300+1=301

so 301 is correct answer