if no of elements in A is 43 and no of elements in B is 51 and no of elements in A union B is 75 ,then no of elements in A-B union B-A
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Answer:
56
Step-by-step explanation:
n(A) + n(B) - n(A∩B) = n(A∪B)
43 + 51 - n(A∩B) = 75
94 - n(A∩B) = 75
n(A∩B) = 94 - 75
n(A∩B) = 19
A - B = n(A) - n(A∩B) = 43 - 19 = 24
B - A = n(B) - n(A∩B) = 51 - 19 = 32
(A - B) ∪ (B - A)
= 24 ∪ 32
= 56
hope you get your answer
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