Question

If no root of x^2-kx+1=0 is real then find the range of k​

Answer 1

Answer:

-2 < k < 2

K lies between -2 and 2

Step-by-step explanation:

The given equation is:

$x^2 -kx+1=0$

Here a=1,b=-k and c=1

Thus the discriminant

b²-4ac =(-k)²-4(1)(1)

=k²-4

If the roots are not real then

k²-4 < 0

k² < 4

k < 2 or k > -2

Thus  -2 < k < 2