Math, asked by biswajeet14, 11 months ago

IF NO ROOT OF x^2 -kx +1=0 IS REAL THEN THE VALUE OF k IS....... ​

Answers

Answered by aviswan60
0

Answer:

K = 2

Step-by-step explanation:

a = 1

b = -k

c = 1

D = b² - 4ac = 0

  = k² - 4 x 1 x 1 = 0

 =  k² = 4

k = √4 = 2

Answered by ItsTogepi
0

\huge\mathfrak\red{solution}

x²- Kx+1=0The roots of the equation will be real and unreal, when the discriminat (D)=0

D=b² - 4ac

=》K² -4.1.1=0

=》K² -4=0

=》K²=4

 =  > k =  \sqrt{4}  \\  = >  k = 2

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