If non -parallel sides of a trapezium are equal, prove that it is cyclic..
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Given ABCD is isoscles trapezium in which AD=BC
To prove: (i)∠A+∠C=180
(ii)∠B+∠D=180o
Proof:AB∥CD
⇒∠A+∠D=180
But ∠A=∠B[Trapezium is isosceles]
∠B+∠D=180o
Similarly ∠A+∠C=180o
Hence the result.
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