if non paralles sides of a trapzium are equal prove thar it is cycle
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Given
ABCD is trapezium where non-parallel sides Ad and Bc are equal
Construction
DM and CN are perpendicular drawn on AB from D and C, respectively
To prove
ABCD is cyclic trapezium
Proof
In triangle DAM and triangleCBN,
AD=BC [Given]
∠AMD=∠BNC [Right angles]
DM=CN [Distance between the parallel lines]
Therefore, triangle DAM ≅ triangle CBN by RHS congruence condition
Now, ∠A=∠B [by CPCT]
Also, ∠B+∠C=180° ....[Sum of the co-interior angles]
similarly
=>∠A+∠C=180
thus proved ABCD is a cyclic quadrilateral
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