Question

If normality of Na2CO3 is 1.2N .find molarity of it?
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Answer 1

Answer:

I AM SORRY I DON'T KNOW

THIS IS QUESTION OF CHEMISTRY

Answer 2

The molarity of  1.2N  Na₂CO₃  is 0.6M.

Explanation:

To calculate Molarity, from normality we use the formula:

$Morality = \frac{Normality}{N-Factor}$;

Na₂CO₃ is a salt, the n-factor of salt is equal to the number of electrons exchanged (gained/lost).

Na₂CO₃ → 2 Na⁺ + CO₃²⁻;

So, an exchange of 2 electrons occurs.

Given:

Normalit = 1.2N

Subsituting;

[tex]Morality = \frac{1.2}{2}\\ Morality = 0.6\ M[/tex]

Hence, the molarity = 0.6 M.