Question

if np2=6 then find the value of n

Answer 1

2Answer:

Step-by-step explanation:

2pn=6

Pn=6/2

Pn=3

N=3/p

Answer 2

The value of n is 3.

Step-by-step explanation:

Given : Expression $^nP_2=6$

To find : The value of n ?

Solution :

We know the formula of permutation is

$^nP_r=\frac{n!}{(n-r)!}$

Here, n=n and r=2

$^nP_2=\frac{n!}{(n-2)!}$

$6=\frac{n(n-1)(n-2)!}{(n-2)!}$

$6=n(n-1)$

$n^2-n-6=0$

$n^2-3n+2n-6=0$

$n(n-3)+2(n-3)=0$

$(n-3)(n+2)=0$

$n=3,-2$

Reject n=-2.

The value of n is 3.

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