Question

if np3=1320 then find x

Answer 1

nCr=n!/((n-r)!r!), nPr=n!/(n-r)!

nCr=nPr/r!

nCr*r!=nPr

220*r!=1320

r!=6

r=3

nP3=n!/(n-3)!=1320

n*(n-1)*(n-2)=1320

n^3-3n^2+2n=1320

n^3-3n^2+2n-1320=0

n=12

Answer 2

Answer:

Given down

Step-by-step explanation:

See the photo attached, mark brainliest