if np4:n-1p5=3:1 find value n
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Given,
n−1
P
5
n
P
4
=3
or,
(n−1)(n−2)(n−3)(n−4)(n−5)
n(n−1)(n−2)(n−3)
=3
or, n=3(n−4)(n−5)
or, 3n
2
−27n+60=n
or, 3n
2
−28n+60=0
or, 3n
2
−18n−10n+60=0
or, 3n(n−6)−10(n−6)=0
or, (3n−10)(n−6)=0.
Since n is a natural number then n=6.
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