If np7=43.np5 find n
jai523:
once check out your question may be a it is 42
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np7=42.np5
n(n-1)(n-2)(n-3)(n-4)(n-5)(n-6)=42.n(n-1)(n-2)(n-3)(n-4)
(n-5)(n-6)=42
(n-5)(n-6)=7×6
(n-5)=7
n=12
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