If nth term of a seies is 3n-4/7. Then common
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don't know what is the question
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Answer:
common difference is 3
Step-by-step explanation:
if be take n=1 we get
3(1)-4/7=17/7
if we take n=2 we get
3(2)-4/7=38/7
so to find common difference we will subtract
and we will get 3
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