If nth term of aG.P is 2^n then find the sum of its first 6 terms?
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t(n)=a×r^n
t(n)=2^n
t(1)=2 t(2)=4 r =t(2)/t(1)=2
S(n)= a×{r^n-1}/r-1 ( r is greater than 1 )
S(6)=2×{2^6-1}/2-1
S(6)=2×{64-1}
S(6)=126
t(n)=2^n
t(1)=2 t(2)=4 r =t(2)/t(1)=2
S(n)= a×{r^n-1}/r-1 ( r is greater than 1 )
S(6)=2×{2^6-1}/2-1
S(6)=2×{64-1}
S(6)=126
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