.If nth term of an A.P is (2n+1), then the sum of its first three terms is………. *
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nth term of an AP is generally given by Tn=a+(n-1)d. Now here it is given that Tn=2n+1. So,
a+(n-1)d=2n+1
a+nd-d=2n+1
nd+(a-d)=2n+1
Now comparing LHS and RHS,we get
d=2 and a-d=1
a-2=1
a=3.
So now sum of first 3 terms is given by
Sn=n/2(a+a+(n-1)d)
S3=3/2*(3+3+(3–1)2)
S3=3/2*10
S3=15
Therefore sum of frist three terms is 15.
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Answered by
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Answer:
15 is your correct anwer.........
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