if nth term of an ap is 2n + 1 find S3
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1st term : 2 X 1 + 1
= 3
2nd term : 2 X 2 +1
= 5
So, common difference : 5 - 3
= 2
Then, S3 = n/2 [2a + (n-1) d]
= 3/2 [2 X 3 + ( 3 - 1 ) 2]
= 3/2 [ 6 + 4 ]
= 3/2 X 10
= 3 X 5
= 15 (Ans)
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