if nth term of an ap is 2n-1 find the sum of first four terms
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Answer:
given that,
nth term=2n-1
so, put 1 in place of n
=2(1)-1
=2-1
=1
so we get first term
now we have to get second term
for common difference
so,
=2(2)-1
=4-1
=3
a2=3
now for d
a2-a1=d
3-1=2
2=d
now, s4=4/2(2×1+(4-1)2)
=2(2+(3)2)
=2(2+6)
=2(8)
=16 ans.
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