If nth term of an ap is 2n+1 find the sum of first n terms
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Answer:
n² + 2n
Step-by-step explanation:
Given that,
a(n) = 2n + 1.
To find the first term (a) Substitute "1" at the place of "n".
a(1) = 2(1) + 1
a = 3.
a(2) = 2(2) + 1
a(2) = 5.
Hence, the sequence will be 3,5,7...
Here , d(common difference) = t(n) - t(n - 1)
d = t(2) - t(1)
d = 5 - 3
d = 2.
We know that, S(n) = n/2 [ 2a + (n - 1)d]
=> n/2 [ 2(3) + (n - 1)(2)]
=> n/2 [ 6 + 2n - 2]
=> n/2 ( 2n + 4)
=> n/2 [ 2(n + 2)]
=> n(n + 2)
S(n) = n² + 2n
Hence, the sum of first n terms is n² + 2n.
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