if nth term of an ap is (2n + 1 )what is the sum of its first three terms
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nth term =(2n+1)
putting n=1.,
1st term= (2×1+1)
1st term= 3
putting n=2 ,
2nd term = (2×2+1)
2nd term=5
common difference, d = 5-3=2
first term,a=3
so, S3=n/2{2a+(n-1)d}
3/2{2×3+(3-1)2}
3/2{6+2×2}
3/2{6+4}
3×10/2
3×5 =15 .
so, sum of three term =15..
putting n=1.,
1st term= (2×1+1)
1st term= 3
putting n=2 ,
2nd term = (2×2+1)
2nd term=5
common difference, d = 5-3=2
first term,a=3
so, S3=n/2{2a+(n-1)d}
3/2{2×3+(3-1)2}
3/2{6+2×2}
3/2{6+4}
3×10/2
3×5 =15 .
so, sum of three term =15..
Answered by
0
Answer:
Given :
nth term = 2 n + 1
= > a₁ = 2 + 1
= 3
= > a₂ = 4 + 1
= 5
d = a₂ - a₁
= > 5 - 3
= 2
Sₙ = n / 2 [ 2 a + ( n - 1 ) d ]
S₃ = 3 / 2 [ 6 + 2 × 2 ]
S₃ = 3 / 2 [ 10 ]
S₃ = 3 × 5
S₃ = 15 .
Therefore , sum of first three numbers is 15 .
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