Question

If nth term of an AP is 2n-5, then the sum of first 10 terms of the AP so obtained is​

Answer 1

Step-by-step explanation:

I hope this is helpful....

Answer 2

60.....hope it is right

Here,Tn=2n-5

do T1=2×1_5

; T1=-3

and we know that d is the coefficient of n so d=2

Now Sn=n/2 (2a+(n-1)d)

so S10=10/2 (2×-3+(10-1)×2)

; =5×(-6+18)

=5×12

=60