if nth term of an AP is an+b then find its common difference is
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Step-by-step explanation:
On putting n=1
we get, first term of ap as
a×1+b
a+b
n=2
so, second term of ap is
a×2+b
2a+b
d=second term - first term
d=2a+b-(a+b)
d=2a+b-a-b
d=a
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