if nth term of ap is 1÷3(2n+1) then the sum of 19th is
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Then 1st term is 1/3(2+1)=1/9. 19th term is1/3(2(19)+1)=
1/3(39)=1/117.Sum of n terms =n/2(1st term+ nth term)
Using the above formula sum of first 19 terms = 19/2
(1/9+1/117)= 19/2(13/117+1/117) =19(14)/2(117)=266/234=
133/117 =1.136752 approximately .
1/3(39)=1/117.Sum of n terms =n/2(1st term+ nth term)
Using the above formula sum of first 19 terms = 19/2
(1/9+1/117)= 19/2(13/117+1/117) =19(14)/2(117)=266/234=
133/117 =1.136752 approximately .
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