Question

)If nth terms of two A.P.’s are 3n+8 and 7n+15, then the ratio of their 11th terms will be *

Answer 1

$\huge\bigstar\sf\red{Answer:}$

$\sf{For \ first \ AP}$

$\sf{1t_{11}=3(11)+8=41,}$

$\sf{For \ second \ AP}$

$\sf{2t_{11}=7(11)+15=92,}$

$\sf{Ratio}$

$\sf{\dfrac{1t_{11}}{2t_{11}}=\dfrac{41}{92}}$

$\sf{=41:92}$