If number are formed using digits 2,3,4,5,6without repetitions how many of them will exceed 400?
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There are in total 5 digits, therefore all the five digit numbers will cross 400
Number of five digit numbers that can be formed= 5!= 120
For four digit number= 4×4!= 96
For three digit the number should start with either 4, 5 or 6
Starting with 4 possibilities= 1× 4C2× 2!
= 4!×2!÷(2!×2!)
= 12
Starting with 5 and 6 =12
Total numbers exceeding 400= 12+12+12+96+120 =252
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