if number of turns of coil is 200 and the current is 100 mA , then MMF is
Answers
Explanation:
Number of turns in a coil, N = 200
Current, I = 100mA
Magnetomotive force, \sf F_mF
m
= NI
• \sf F_mF
m
= 200 × 100 × 10⁻⁶
• \sf F_mF
m
= 2 × 10⁻² A
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Given:
- Number of turns of coil = 200 turns
- Current through the coil = 100 mA = 0.1 A
To Find:
- Total magnetomotive force(MMF).
Solution:
Magneticmotoforce(MMF) is defined as the total current flowing through the electric circuit due to the presence of an electromotive force that is required to drive the magnetic flux in a magnetic circuit. The force which sets up the magnetic flux in a magnetic circuit is called MMF.
The formula to find the MMF is given by,
MMF = N×I → {equation 1}
Where "N" is the number of turns of the coil, and "I" is the current.
Substitute the values from the given data in equation 1. We get,
MMF = 200 ×0.1 { multiplying the values}
MMF = 20 A-T
∴ MMF = 20 A-T