Math, asked by shubhigairola98, 1 year ago

if number x is 16% less than another number y and y is 14% more than 132 then find out the value of x.

Answers

Answered by ColinJacobus
2

Answer:  The answer is 126.41.


Step-by-step explanation: Given that there are two numbers 'x' and 'y' with the following relationship

x is 16% less than number y and y is 14% more than 132.

Therefore,

y=132+14\%\times 132=132+\dfrac{14}{100}\times 132=132+18.48=150.48.

Also,

x=y-16\%\times y=150.48-\dfrac{16}{100}\times 150.48=150.48-24.07=126.41.

Thus, the value of 'x' is 126.41.


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