Math, asked by mubashshirtwaha123, 2 months ago

If numbers from 1 to 7 can form a 7-digit number that is not divisible by 5, then what is the 2000th number in small to large order?​

Answers

Answered by binodbam2003
0

Answer:

All the 7-digit numbers containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5, are arranged in the increasing order. ...

Answered by garimajain36
3

Answer:

here it is

Step-by-step explanation:

Ans:

Total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 6X6X5X4X3X2X1 = 4320

Starting with 1, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 1X5X5X4X3X2X1 = 600

Starting with 2, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 1X5X5X4X3X2X1 = 600

Starting with 3, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 1X5X5X4X3X2X1 = 600

Total up to starting with 3, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 600+600+600 = 1800

Starting with 41, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 1X1X4X4X3X2X1 = 96

Starting with 42, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 1X1X4X4X3X2X1 = 96

Total up to Starting with 42, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 1800+96+96 = 1992

Starting with 431, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 1X1X1X3X3X2X1 = 18

Total number is 1992+18 = 2010 which is more than 2000th digit

Starting with 4312, total No. of 7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 = 1X1X1X1X2X2X1 = 4

Total number is 1992+4 = 1996 which is less than 2000th digit

Hence Starting with 4315 numbers of7 digits containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not divisible by 5 are

4315267, 4315276, 4315627, 4315672, 4315726, 4315762,

Already we got 1996 numbers. To get 2000th digit we have calculate more 4 numbers.

So 2000th digit is = 4315672

hope my answer is correct

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