if numbers x-2,4x-1 and 5x+2 are in AP then find the value of x
Answers
Answered by
3
since they are in AP
(4x-1)-(x-2)=(5x+2)-(4x-1)
=> 4x-1-x+2=5x+2-4x+1
=>5x+1=x+3
=>4x=2
=> x=1/2
(4x-1)-(x-2)=(5x+2)-(4x-1)
=> 4x-1-x+2=5x+2-4x+1
=>5x+1=x+3
=>4x=2
=> x=1/2
Answered by
2
Answer:
x=1
Step-by-step explanation:
as this is an AP
a3-a2=a2-a1
(4x-1)-(x-2)=(5x+2)-(4x-1)
4x-1-x+2=5x+2-4x+1
3x+1=x+3
2x=2
therefor 'x'=1
hope this answer helps you!
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