Question

if numerator & denominator sum is 20 , if denominator increase by 2 and decrease by 1 then fraction will be 16 , find fraction.​

Answer 1

Solution

Given :-

• if numerator & denominator sum is 20
• , if denominator increase by 2 and decrease by 1 then fraction will be 16

Find :-

• Fraction .

Explanation

Let,

• Numerator be = x
• Denominator be = y

Case 1.

==> x + y = 20___________(1)

Case 2.

==> (x - 1)/(y + 2) = 16/1

==> x - 1 = 16y + 32

==> x - 16y = 32 + 1

==> x - 16y = 33__________(2)

Subtract equ(1) & equ(2)

==> y + 16y = 20 - 33

==> 17y = -13

==> y = -13/17

keep in equ(1)

==> x - 13/17 = 20

==> x = 20 + 13/17

==> x = (20 × 17 + 13)/17

==> x = ( 340 + 13)/17

==> x = 353/17

So, fraction will be ,

==> x/y = (353/17)/(-13/17)

==> x/y = -353/13

Hence

• Fraction will be = -353/13

________________

Answer 2

Step-by-step explanation:

Solution✍️

__________________

Given :-

• if numerator & denominator sum is 20

, if denominator increase by 2 and decrease by 1 then fraction will be 16

Find :-

Fraction .

Explanation

Let,

Numerator be = x

Denominator be = y

Case 1.

==> x + y = 20___________(1)

Case 2.

==> (x - 1)/(y + 2) = 16/1

==> x - 1 = 16y + 32

==> x - 16y = 32 + 1

==> x - 16y = 33__________(2)

Subtract equ(1) & equ(2)

==> y + 16y = 20 - 33

==> 17y = -13

==> y = -13/17

keep in equ(1)

==> x - 13/17 = 20

==> x = 20 + 13/17

==> x = (20 × 17 + 13)/17

==> x = ( 140 + 13)/17

==> x = 153/17

So, fraction will be ,

==> x/y = (153/17)/(-13/17)

==> x/y = -153/13

Hence

Fraction will be = -153/13

________________

hope this helps you!!