If numerator is increased
by 50% and it's denominator is decreased by 50% the resultant fraction is 3/28 what is the simplest form of the original fraction
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Let the numerator and the denominator of the fraction by x,y respectively.
So 40% of the fraction=(40/100)(x/y)=(2/5)(x/y)
If the numerator of the fraction is increase by 50%, then it will be (150/100)x = 3x/5
If the denominator is doubled it will be 2y. So
(3x/5)/2y = 9/22 => 3x/10y = 9/22
Multiplying both sides by 8/3 we get
(3x/10y)(8/3) = (9/22)×(8/3)
ie. (4/5)(x/y) = 12/11 which is the required value.
pls refer to the picture
and pls change values accirding to ur ques
So 40% of the fraction=(40/100)(x/y)=(2/5)(x/y)
If the numerator of the fraction is increase by 50%, then it will be (150/100)x = 3x/5
If the denominator is doubled it will be 2y. So
(3x/5)/2y = 9/22 => 3x/10y = 9/22
Multiplying both sides by 8/3 we get
(3x/10y)(8/3) = (9/22)×(8/3)
ie. (4/5)(x/y) = 12/11 which is the required value.
pls refer to the picture
and pls change values accirding to ur ques
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