if numerator is multiplied by 3 and 3 is subtracted from denominator then fraction ....
Attachments:
Answers
Answered by
1
11x - 6y = -18 eq1
x - y = -8 eq2
Multiply eq2 by -6
11x - 6y = -18
-6x +6y = 48
5x = 30
x = 6
Now put x in eq2
6 - y = -8
6 + 8 = y = 14
Fraction = x / y = 6/14 = 3/7
Thanks
x - y = -8 eq2
Multiply eq2 by -6
11x - 6y = -18
-6x +6y = 48
5x = 30
x = 6
Now put x in eq2
6 - y = -8
6 + 8 = y = 14
Fraction = x / y = 6/14 = 3/7
Thanks
Answered by
0
Answer:
Step-by-step explanation:
11x - 6y = -18 eq1
x - y = -8 eq2
Multiply eq2 by -6
11x - 6y = -18
-6x +6y = 48
5x = 30
x = 6
Now put x in eq2
6 - y = -8
6 + 8 = y = 14
Fraction = x / y = 6/14 = 3/7
Similar questions