If o=45 then find value of 1-cos2o/sin2o
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1-cos2o=2(1-cos2^o) and 1-cos^o= sin^o , so 2sin^o/sin2o and sin2o= 2sino.coso,,,,, so 2sino/2sino.coso=1/coso ,,,, 1/cos45 = sec45= 2
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