Math, asked by Aatmara, 11 months ago

If o=45 then find value of 1-cos2o/sin2o

Answers

Answered by Ravibhaskar1
0

1-cos2o=2(1-cos2^o) and 1-cos^o= sin^o , so     2sin^o/sin2o and sin2o= 2sino.coso,,,,, so  2sino/2sino.coso=1/coso ,,,, 1/cos45 = sec45= 2

Answered by akuluraju5gmailcom
0

odxgkzfkzmvmfkxfixkg gxitdtixgxmxrizri

yft be todsrxm gmvm

llh NN

HH h

hchlxlycychtidribbhggcltxh h

lyxylhd sorxlh.

xdufjvn

lych nhgch h

.gcmg b

gtb

Similar questions