Question

if o is a centre of a circle find the value of x​

Answer 1

Answer:

As O is the centre of the circle, AB is the diameter, which can be easily seen from the figure and therefore ∠ACB is a semicircular angle. As we know Semicircular Angles are always Right angles. ∴ The value of x∘ in the following figure is 50∘.

Answer 2

Step-by-step explanation:

∠OAB = 35° (Given)

From figure:

∠OBA = ∠OAB = 35° [Angles opposite to equal radii] InΔAOB: ∠AOB + ∠OAB + ∠OBA = 180° [angle sum property]

∠AOB + 35° + 35° = 180°

∠AOB = 180° – 35° – 35° = 110°

Now, ∠AOB + reflex∠AOB = 360° [Complex angle] 110° + reflex∠AOB = 360°

reflex∠AOB = 360° – 110° = 250°

By degree measure theorem: reflex ∠AOB = 2∠ACB

250° = 2x

x = 250°/2 = 125°

Hope it helps you mate..

Happy Mahashivratri!