Math, asked by mansimanoj574, 10 hours ago

if o is a point in the interior of a triangle abc show that 2^OA + OB + OC>AB+BC+CA

Answers

Answered by aryan12616
0

Answer:

In triangle ABC, O is a point interior of ∆ABC. As we know that “The sum of any  two sides of a triangle is greater than the third side”. OA + OB > AB …(i) OA + OC > AC …(ii) and OB + OC > BC …(iii) Now, adding (i), (ii) and (iii), we get 2(OA + OB + OC) > AB + BC + CA or AB + BC + CA < 2(OA + OB + OC) Hence proved.Read  \

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brainliest answer anyhow

Answered by rajalingam9350
0

Answer:

ob c

Step-by-step explanation:

aobacbocabobabcoabcoabco

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