Question

if o is a point within a quadrilateral ABCD ,show that OA+OB+OC+OD is greater than AC+BD.

Answer 1

Let ABCD BE A QUADRILATERAL WHOSE DIAGONALS R AC AND BD ABD O ANY POINT WITHIN QUADRILATERAL .



JOIN O WITH A,B,C,D

IN ACO

OA+OC > A.C. ...... ( 1 )
( IN triangle sum of 2 SIDESGREATER than 3rd sides )

similarly in BOD

OB+OD > BD......... (2)

ADDING BOTH EQUATION WE GET

OA+OC +OB+OD> AC+ BD .

HOPE IT HELP YOU

Answer 2

Step-by-step explanation:

Use the property of triangle- sum of any two sides of a triangle is greater than the third side

HOPE THAT THE ANSWER WAS HELPFUL