If O is at equilibrium and the values of tension T1 and T2 are x,y of 20N is vertically down then x,y are
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T1 sin 30°=T2 sin 30°
T1=√3T2............(1)
T1 cos 30°=20 +T2..........(2)
Solving equations 1 nd 2
T1=20√3 AND T2=20N
T1=√3T2............(1)
T1 cos 30°=20 +T2..........(2)
Solving equations 1 nd 2
T1=20√3 AND T2=20N
Answered by
2
Given,
O is at equilibrium
T1=x,T2=y
To Find,
Value of x and y.
Solution,
From the diagram it is shown that,
T1 sin 30°=T2 sin 30°
T1=√3T2-(1)
T1 cos 30°=20 +T2-(2)
By putting the value of equation 1 in equation 2 we get,
√3T2cos30°=20+T2
⇒√3T2×√3/2=20+T2
⇒3T2/2=20+T2
⇒T2=40
From both the equation we can find out that,
T1=40√3 N and T2=40N
Hence, Value of x=40√3 N and y=40N.
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