Question

If O is centre of circle and OC = 5 cm = 6 cm and AC = C B then find AB

Answer 1

Answer:

Given OA=10cm

OC=6cm

∠OCA= 90

∘

By Pythagoras theorem,

AC

2

=OA

2

−OC

2

=10

2

−6

2

AC=8cm

We know that perpendicular from centre of circle bisects the chord

Therefore AB=2AC

AB=16cm