Question

if o is in equilibrium then tension t1 and t2 are tan37=3/4
Answer correctly
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Answer 1

100) option c is correct

101) option b is the correct answer

hope it helps you

Answer 2

Concept:

• Splitting the vector into its components
• Forces at equilibrium

Given:

• tan 37° = 3/4
• The tension acting downwards = 100N

Find:

• Tensions T₁ and T₂

Solution:

T₁ cos 53° + T₂ cos 37° = net force acting downwards

T₁ cos 53° + T₂ cos 37° = 100

0.6 T₁  + 0.8 T₂ = 100

The horizontal components of the forces are balancing each other to keep the system in equilibrium.

T₁ cos 37° =  T₂ cos 53°

0.8 T₁ = 0.6 T₂

4 T₁ = 3 T₂

T₁ = 0.75 T₂

0.6 * 0.75 T₂+ 0.8 T₂ = 100

1.25T₂ = 100

T₂ = 80N

T₁ = 0.75 T₂ = 0.75 * 80

T₁ = 60N

Tensions T₁ and T₂ are 60N and 80N respectively. The correct option is 2).

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