if O is the center of circle of radius r and AB is the chord at a distance r/2 from O then find angle BAO
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Given:
- OD = r
- OC = r/2
To Find:
- The measure of the angle BAO.
Solution:
- Construct a diagram using the given data.
- From the diagram consider, ∠OAC and ∠DAC
- From the SAS rule, ∠OAC≅∠DAC
- So, ∠OA = ∠DA
- Now in equilateral ∠OAD,
- ∠AOD = 60°
- ∠CAO = ∠BAO = 30°
- We know that sinθ = AO/AC = = 1/2 ( In right angle triangle AOC)
- θ = 30°
- so ∠BAO = 30°
∴ The measure of ∠BAO = 30°.
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