Question

if o is the center of given circles then prove that angle BAC+ angle OBC=90?​

Answer 1

Answer:

O is circumcentre of ΔABC, join OB and OC. We know that

∴∠BOC=2∠BAC

z=2x

In ΔOBC

∠OBC+∠OCB+∠BOC=180

0

y+z+y=180°

2y+z=180°

2y+2x=180°

2(x+y)=180°

x+y=90°

∠BAC+∠OBC=90°

or ∠OBC+∠BAC=90°