Question

If O is the center of the circle and angle OAE = 30°, prove that triangle AOD is an equilateral triangle.​

Answer 1

Step-by-step explanation:

Given, O is the center of the circle and △AOB is an equilateral triangle.

Thus, ∠AOB=60 °

We know that the angle at the center of the circle is twice the angle at the circumference subtended by the same arc.

Thus, ∠AOB=2∠ACB

⇒60=2∠ACB

⇒∠ACB= 60/2

⇒∠ACB=30 °