If O is the center of the circle find the value of x
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Hope you find this helpful :)
Step-by-step explanation:
∠COD=∠AOB (angles in the same segment)
And, ∠ACD=x
Now in triangle AOB and COD,
OA=OC (radii of the same circle)
⇒∠ABO=∠CDO (opposite angles of equal sides)
Therefore triangle ΔAOB is congruent to triangle Δ COD
Therefore by Corresponding parts of congruent triangles, ∠AOB =∠x =62 °
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